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Answer:
tan²θ + cot²θ = 2.
Step-by-step explanation:
{Formulae used:
- (a+b)² = a²+b²+2.a.b
- cotθ = 1/tanθ}
tanθ + cotθ = 2.
Square on both sides,
(tanθ + cotθ)² = 2².
tan²θ + cot²θ + 2 . tanθ . cotθ = 4
tan²θ + cot²θ + 2 . tanθ . 1/tanθ = 4
tan²θ + cot²θ + 2 = 4
tan²θ + cot²θ = 4 - 2
tan²θ + cot²θ = 2.
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