Question

Answer this If U REAL GENIUS ; )​

Answer 1

hey mate:

given here:

equation of plane is

2x-3y+6z-11=0.

normal to tha plane is n= 2i-3j+6k

also , x-axis along the vector

ā= î + 0j + 0k

let here

alpha =p

according to the question:

sin p = |ā.ñ|/|ā||ñ|

so,

sin p = (ì).(2i-3j+6k)/√(1²)√[(2²+(-3)²+6²)]

sin p = 2/√(4+9+36)

= 2/√49

=2/7

I hopes its helps u.

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