Question

Answer this Math Ques. class 10.please...

Answer 1

$\huge\boxed{\red{K=5\:and\:a=\:-5}}$

$\blue{we \: know \: that \: divident = divisor \times quotient + remainder}$

$\pink{divident-remainder=divident×quotient}$

$\green{divident-remainder =is \: divisible \:by \:the\: divident}$

$\large{(now \:see\: attachment}$°_°)

$(- 10 + 2k) = 0 \: and \: 10 - a + 8k + {k}^{2} = 0$

$2k = 10 \\k = \frac{10}{2}$

$\large\bold{\underline{\underline{K=5}}}$

$\large{10-a+8(5)+{5}^{2}}$

$\large{-a=-19+40-25}$

${-a=5}$

$\large\bold{\underline{\underline{a=-5}}}$

$\huge\bold{\green{HOPE\: IT \:HELPS}}$