Math, asked by XxMissInnocentxX, 1 month ago

Answer This:-
๑MoDs
๑Stars
๑Best Users
$\huge \tt \red{Question - }$
★ Two spheres of masses 20 g and 40 g moving in a straight line in the same direction with velocities of 3 mIs and 2 m/s respectively. They collide with each other and after the collision, the sphere of mass 20 g moves with a velocity of 2.5 miles. Find the velocity of the second ball after confusion.

Answers

Answered by Zahrah2008

Answer:

Here, m

Here, m 1

Here, m 1 =10g=

Here, m 1 =10g= 1000

Here, m 1 =10g= 100010

Here, m 1 =10g= 100010 =0.01kg

Here, m 1 =10g= 100010 =0.01kgm

Here, m 1 =10g= 100010 =0.01kgm 2

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kg

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?Total momentum of both the spheres before collision =m

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?Total momentum of both the spheres before collision =m 1

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?Total momentum of both the spheres before collision =m 1 u

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?Total momentum of both the spheres before collision =m 1 u 1

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?Total momentum of both the spheres before collision =m 1 u 1 +m

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?Total momentum of both the spheres before collision =m 1 u 1 +m 2

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?Total momentum of both the spheres before collision =m 1 u 1 +m 2 u

Here, m 1 =10g= 100010 =0.01kgm 2 =20g=0.02kgu 1 =3ms −1 ;u 2 =2ms −1 v 1 =2.5ms −1 ;v 2 =?Total momentum of both the spheres before collision =m 1 u 1 +m 2 u 2

Step-by-step explanation:

Helps you

Answered by XxitzCottonCandyxX

Answer:

★ For sphere A

• Mass = 20 g

• Initial velocity = 3 m/s

• Final velocity = 2.5 m/s

★ For sphere B

Mass = 40 g

Initial velocity = 2 m/s

★ We have to find final velocity of sphere B after collision.

Since no external force acts on the

system of sphere, momentum of whole

system is conserved.

Initial momentum of system will be equal to the final momentum of system.

Momentum is measured as the product of mass and velocity.

> P = mxv

➠ P (initial) = P (final)

➠ m₁U₁ + m₂U₂ = M₁V₁ + M₂V2

➠ 20(3) +40(2) = 20(2.5) + 40V2

➠ 60+80= 50 + 40v₂

➠ 40v₂ = 90

➠ V₂ = 2.25 m/s

Previous Question

Next Question