Question

Answer this
No spamming​

Answer 1

Aasalamu-ali-kum Mate!

Answer 2

Answer:

Option a)

Step-by-step explanation:

Given :

$a = log_{24}12$

Correction in Question : $a = log_{12}24$ won't yield any of the options),.

$b = log_{36}24$

$c = log_{48}36$

Then, find :

1 + abc = ?

Solution :

We know that,

⇒ $log_xy \times log_yz = log_xz$

⇒ ∴ $bc = log_{36}24 \times log_{48} 36 = log_{48}24$ ...(i)

⇒ ∴ $abc = a \times bc = log_{24}12 \times log_{48}24 = log_{48} 12$

⇒ ∴ $1 + abc = 1 + log_{48}12 = log_{48}48 + log_{48}12 = log_{48}48\times 12 = log_{48}576$

⇒ $log_{48}576 = log_{48}24^2$

⇒ $log_{48}24^2 = 2log_{48}24 =2bc$  (from (i) )

∴ Option a) is correct,.