Question

answer this.
no spammmmmm

Answer 1

Explanation:While filling 5th shell according to aufbau principle 5s,5p.4d filled so 2 +6 +10 =18 electrons or elements are present in 5th shell. We start the 5th period with 4s orbital. We can add 2 electrons in 4s. Then we fill 6 electrons in 4p orbital.  

hope it helps!!!

Answer 2

$\bold{Hello!}$

______________

when n = 5,
l= 0,1,2,3

The order in which the energy of the available orbitals 4d, 5s and 5p increases is 5s < 4d < 5p.
The total number of orbitals available are 9. The maximum number of electrons that can be accommodated is 18,

and therefore 18 elements are there in the 5th period.