Question

Answer this numerical -

an electron renters with magnetic field of 5 Tesla! and velocity of 5 × 10^6 m/s . The angle ∅ = 30° find F​

Answer 1

${\mathcal{\bold{\red{Hey\:Mate!!}}}}$

Here's the Answer ❗

${\bold{Given\:That}}$→

♦Magnetic Field ( B ) = 5 Tesla

♦Velocity ( V ) = $5 × 10{}^6$ m/s

♦Angle ∅ = 30°

♦Charge (q) = $1.6 \times 10 {}^{ - 19}$

We know that , force in a magnetic field is given by the formula →

${\boxed{\boxed{\bold{F = q.V.B Sin@}}}}$

So we have

$f = 1.6 \times 10 {}^{ - 19} \times \frac{1}{2} \times 5 \times 5 \times 10 {}^{6} \\ = > 2 \times 10 {}^{ - 12}$

•°• ${\bold{Answer}}$→ $2 \times 10 {}^{ - 12}N$

__________________________________________________

Answer 2

Answer:

Force = q ( V × B )

= 1.6 × 10^-19 × 5 × 10^6 × 5 × sin 30

= 2 × 10^-12 Newton which is the force in the field