Answer this
On rationalizing the denominator of
we get
Answers
Answered by
1
Step-by-step explanation:
1/√7-√6
1/√7(√7÷√7)-√6
(√7/7)-√6
(√7-7√6)/7
Answered by
33
Given
1/√7 - √6
Rationalize its denominator
Solution
→ 1/√7 - √6
→ 1/√7 - √6 × √7 + √6/√7 + √6
★ Applying identity :
a² - b² = (a + b)(a - b)
→ √7 + √6/(√7)² - (√6)²
→ √7 + √6/7 - 6
→ √7 + √6/1
→ √7 + √6
Some identities
- (a + b)² = a² + b² + 2ab
- (a - b)² = a² + b² - 2ab
- a³ - b³ = (a - b)(a² + ab + b²)
- a³ + b³ = (a + b)(a² + ab + b²)
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