Question

answer this one easy ​

Answer 1

Answer:

i don't know the answer

Answer 2

Answer:

no it is not quadratic equations

Step-by-step explanation:

x ( x + 2 ) = x^ 2 + 5x + 6

x ^ 2 + 2x = x ^ 2 + 5x + 6

X 2 cancel out from both side

if quartartic number is cancel or not there

then it is not quadratic equation.......

2 equation :.

x ^ 2 + 4x - 4 = 0

D = b^ 2 - 4ac = 16 - 4× 4 × 1 = 16 - 16 = 0

then it have one root real and equal

X = - b ^ + √ b^ 2 - 4ac / 2a

= - 4 / 2 = -2