Question

answer this one plsss ​

Answer 1

Answer:

⇝Answer:

GIVEN:

. Cone → h = 14 cm ; r = 5 cm

When an object is reshaped, the volume remains the same ,

. Volume of cone = Volume of sphere

\implies \large {\frac{1}{3} \pi {r}^{2} h = \frac{4}{3} \pi {R}^{3} }⟹31πr2h=34πR3

\implies \large {\frac{1}{3} \pi( {r}^{2} h) = \frac{1}{3}\pi (4 {R}^{3} )}⟹31π(r2h)=31π(4R3)

. ❌ Cancelling out 1/3π , ❌

\implies \large{ {5}^{2} \times 14 = 4 {R}^{3} }⟹52×14=4R3

\implies \large {R}^{3} = \frac{7}{2} \times 25⟹R3=27×25

\implies \large \: {R}^{3} = 875⟹R3=875

\huge \boxed {\leadsto \: {R}^{3} = \sqrt{875} \: cm}⇝R3=875cm

Answer 2

Answer:

HOPE IT HELPS YOU DEAR ARMY PLZ DON'T REPORT THE ANSWER ALREADY SOO MANY AMSWERS ARE REPORTED