Question

answer this physics question.. ​

Answer 1

Answer:

Power of heater, P = 600 W

Mass of liquid, m = 4.0 kg

Change in temperature of liquid = (15 − 10)^oC = 5^oC(or 5 K)

Time taken to raise its temperature = 100s

Heat energy required to heat the liquid

ΔQ = mcΔT And

ΔQ = P × t = 600 × 100 = 60000J c = ΔQ/mΔT

= 60000/4 x 5 = 3000 Jkg-1K-1  

Heat capacity = c × m

Heat capacity = 4 × 3000JKg-1 K-1 = 1.2 × 104 J/K

Hope this helps....

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