Question

answer this please 1/x^-5​

Answer 1

$\frac{1}{ {(x)}^{ - 5} }$

$\sf \purple{ we \: know \: that : }$

$\red{ \boxed{ \frac{1}{ {(a)}^{ - m} } = {a}^{m} }}$

$\boxed{ \orange{ \therefore \frac{1}{ {(x)}^{ - 5} } = {x}^{5} }}$

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Answer 2

Answer:

B

Step-by-step explanation:

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(1) x^2 > 5

(2) x^2 + x < 5

We need to determine whether x < 5.

Statement One Alone:

x^2 > 5

If x = 3, then x is less than 5. However, if x = 6, then x is not less than 5. Statement one alone is not sufficient to answer the question.

Statement Two Alone:

x^2 + x < 5

Thus, we have x < 5 - x^2. Since x^2 is nonnegative, we have 5 - x^2 ≤ 5. Since x < 5 - x^2 and 5 - x^2 ≤ 5, we have x < 5.

Answer: B