Answer this please!
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using property of logarithm we know that if base and argument of log are positive then value of log is also positive ..
and we can see that
A = 1.49 ( approximately)
B = 1.49 (approximately)
so value of log is is 1
which is positive integer.
_________________-___________
hope it will help u
and we can see that
A = 1.49 ( approximately)
B = 1.49 (approximately)
so value of log is is 1
which is positive integer.
_________________-___________
hope it will help u
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Divyankasc:
Thanks!!! :D
Answered by
5
B = 12/( 3 + √5 + √8 )
= 12/( 1+ √2² + √5 + 2√2)
= 12/{ (1² +√2² + 2√2) +√5}
= 12/{ (1 +√2)² + √5}
= 12× { ( 1+√2)² - √5}/{ (1+√2)⁴ -√5² }
=12{ (1 +√2)² -√5}/{ 17 + 12√2 -5 }
= { (1+√2)² -√5}/( 1+ √2)
= ( 1 + √2) -√5/( 1+√2)
= 1 + √2 - √5× (√2 -1)/( √2² -1)
= 1+ √2 -√10 +√5
hence, B = √1 + √2 + √5 -√10
and given A = √1 +√2 + √ 5 -√10
hence, A = B
so, log( B base A ) = 1
so,
log( B base A ) is a positive integer .
= 12/( 1+ √2² + √5 + 2√2)
= 12/{ (1² +√2² + 2√2) +√5}
= 12/{ (1 +√2)² + √5}
= 12× { ( 1+√2)² - √5}/{ (1+√2)⁴ -√5² }
=12{ (1 +√2)² -√5}/{ 17 + 12√2 -5 }
= { (1+√2)² -√5}/( 1+ √2)
= ( 1 + √2) -√5/( 1+√2)
= 1 + √2 - √5× (√2 -1)/( √2² -1)
= 1+ √2 -√10 +√5
hence, B = √1 + √2 + √5 -√10
and given A = √1 +√2 + √ 5 -√10
hence, A = B
so, log( B base A ) = 1
so,
log( B base A ) is a positive integer .
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