Question

Answer THIS PLEASE
A clock was 2 mimutes late at 8 O' clock in the morning and 1 minute fast at 6'O clock in the evening. If the clock running fast uniformly at what time did the clock show the right time? Please explain.​

Answer 1

Answer:

2:40 afternoon

Step-by-step explanation:

difference between. timing = 2-(-1)= 3 minutes

difference of time= 12+(6-8)= 10 hours

10 hours => 3 minutes

1 hour => 3/10 minute= 3×60/10= 18 seconds

since clock is 2 minute late

=> time interval at which it show right time

= 2×60/18= 6+2/3 hours= 6 hours+ 40 minutes

time =( 8+6) o clock and 40 minutes

= at 2 : 40 afternoon it gives right time

other method

3 : 10 : : 2 : x

x= 10×2/3= 6 hours+ 2/3 hour

6 hours+ 40 minutes

required time = 8+6 : 40 PM

= 2: 40 PM