Question

Answer this please in trigonometry

Answer 1

Here x is the distance between ships.
And y is the distance between the nearest ship and lighthouse.

Using 'tan' I have found the answer.

Answer 2

Let AB be the lighthouse of height 75 m.
Let C and D be the positions of the ships.
30° and 45° are the angles of depression from the lighthouse.
A/q,
In  right ΔABC,
tan 45° = AB/BC
⇒ 1= 75/BC
⇒ BC = 75 m
also,
In  right ΔABD,
tan 30° = AB/BD
⇒ 1/√3 = 75/BD
⇒ BD = 75√3  m

The distance between the two ships = CD = BD - BC = (75√3 - 75) m = 75(√3-1) m.