Question

Answer this please its urgent

Question 1.
Abscissa of a point is positive in
(а) I and II quadrants
(b) I and IV quadrants
(c) I quadrants only
(d) II quadrant only.


Question 2.
The points (-5, 2) and (2, -5) lie in the
(а) same quadrant
(b) II and III quadrant respectively.
(c) II and IV quadrant respectively.
(d) I and IV quadrant respectively

Question 3.
If (x + 2, 4) = (5, y – 2), then coordinates (x, y) are
(a) (7, 12)
(b) (6, 3)
(c) (3, 6)
(d) (2, 1

Question 4.
Mirror image of the point (9, -8) in y-axis is
(a) (-9, -8)
(b) (9, 8)
(c) (-9, 8)
(d) (-8, 9)


please answer I will mark branliest who will answer it perfectly ​

Answer 1

Answer:

1)b

2)a

3)b

4)c

Step-by-step explanation:

hope it is helpful

Answer 2

Answer:

1) b

2) Sorry I don't know.

3) c

4)a

Step-by-step explanation:

1) The distance along the horizontal axis. A coordinate is an ordered pair of numbers in which the first number is the abscissa i.e. the measurement along the X axis. So, the abscissa of the point is positive in the first and fourth quadrant.

2) Sorry I don't know

3) ( x+2, 4) = (5, y–2)

Here, compare x coordinate with x coordinate and y coordinate with y.

So, x+ 2 = 5 and 4 = y-2

⇒ x = 5 - 2 =3

and 4 + 2 = y = 6

So, x = 3 , y = 6

and (3,6) is the required coordinate.

4) The given point is (9, - 8)

We have to find the mirror image of this point with respect to the y-axis, i.e., the mirror image is a point whose distance is same from the origin O (0, 0) and same from both axes as of the point (9, - 8) is.

Since (9, - 8) lies on the fourth quadrant, the mirror image with respect to the y-axis must lie on the third quadrant. In third quadrant, the x-coordinate of any point (x, y) is negative.

Here the mirror image is (- 9, - 8).