Question

answer this please its urrgent​

Answer 1

Answer:

a = 0.2m/s^2. S= 7.5m

Explanation:

convert km/h into m/s by multiplying by (5/18)

a = (v - u)/t

a = (2 - 1)/5

a = 0.2m/s^2

now v^2 = u^2 +2as

2^2 = 1^2 + 2*0.2*s

4 - 1 = 0.4 * s

3/0.4 = s

s= 7.5

s is called distance

Answer 2

Given:-

• Initial velocity, u = 18km/h = (in m/s) = 18×1000/3600 = 5m/s
• Final velocity, v = 36km/h = (in m/s) = 36×1000/3600 = 10m/s
• Time, t = 5s

To Find:-

• Acceleration, a
• Distance covered, d

____________________

$\huge{ \boxed{ \sf \: For \: \: 1 }}$

From Newton's 1st law of motion

$\: \: \: \: \: \: \: \: \large \sf \boxed{ \red{ \sf \: v=u+at}}$

$\: \: \: \: \: \: \: \: \large \boxed{ \sf \red{a = \frac{v - u}{t} }}$

Now put the values in above formula,

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large \implies{ \sf \red{a = \frac{10 - 5}{5} }}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large \implies{ \sf \red{a = \frac{ \cancel5}{ \cancel5} = 1m {s}^{ - 2} }}$

$\huge{ \boxed{ \sf{ For \: \: 2}}}$

From Newton's 2nd law of motion,

$\: \: \: \: \: \: \: \: \large \sf \boxed{ \pink{ \sf{s = ut + \frac{1}{2} a {t}^{2} }}}$

Now put the values in above formula,

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large \implies{ \sf{ \pink{s = 5 \times 5 + \frac{1}{2} \times 1 \times {5}^{2} }}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large \implies{ \sf \pink{s = 25 + 12.5}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large \implies{ \sf \blue{s = 37.5m}}$