Question

answer this please its very urgent

Answer 1

so your answer is (b) p/r

hope it helps u....

mark as brainlist if you are satisfied with the ans....

BTS❤❤❣ARMY✌✌✌✌

Answer 2

$Compare \:p(x) = x^{3} +px^{2}-pqrx + r \: with \\ax^{3} + bx^{2} + cx + d, \: we \:get$

$a = 1 , \:b= p , \: c = -pqr , \: d = r$

$Given \: \alpha , \beta \: and \: \gamma \: are \\zeroes \: of \: p(x)$

$i) \alpha + \beta+\gamma = \frac{-b}{a} \\= \frac{-p}{1} \\= -p \: ---(1)$

$ii) \alpha \beta\gamma = \frac{-d}{a} \\= \frac{-r}{1} \\= -r \: ---(2)$

$Now, Value \:of \: \frac{1}{\alpha \beta} + \frac{1}{\beta \gamma} +\frac{1}{\gamma \alpha} \\= \frac{\alpha + \beta + \gamma }{\alpha \beta\gamma}\\= \frac{-p}{-r} \\= \frac{p}{r}$

Therefore.,

$Option \: \pink { (b) }\: is \: correct.$

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