Math, asked by madhuryamohan2008, 1 month ago

answer this please. l will mark as brainiest​

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Answered by lathaashokiyer
2

Answer:

The population of a town increases every year by 10%. If the present population is 180,000, what will be the population of the town after 2 years?

Let the population of the town after 2 years be x

Increase percent of population every year = 10%

Present population = 180000

= 10% of 180000

= 10/100 * 180000 = 10*1800 = 18000

Increase in population after 1 year = 180000+18000 = 198000

Increase in population afer 2 years = 10% of population in 1 year + population of 1 year

= 10% of 198000+198000

= 10/100 * 198000 = 10*1980 = 19800

= 198000+19800 = 217800

Therefore, the population of the town after 2 years is 2,17,800.

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Answered by manabikasaha2009
0

The above picture contains the answer...

hope it helps u....

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