Question

answer this please.. plz tell correct answer​

Answer 1

) In △ABD and △ACD, 

AB=AC         ....(since △ABC is isosceles) 

AD=AD        ....(common side)

BD=DC        ....(since △BDC is isosceles) 

ΔABD≅ΔACD     .....SSS test of congruence, 

∴∠BAD=∠CAD i.e. ∠BAP=∠PAC          .....[c.a.c.t]......(i)

(ii) In △ABP and △ACP, 

AB=AC          ...(since △ABC is isosceles)

AP=AP         ...(common side)

∠BAP=∠PAC      ....from (i)

△ABP≅△ACP    .... SAS test of congruence

∴BP=PC      ...[c.s.c.t].....(ii)

∠APB=∠APC     ....c.a.c.t.

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Answer 2

Answer:

i. ∆abd congruent ∆ acd

AD is common to AD so they are equal { AD= AD }

now BCD is a isosceles triangle so BD and CA are equal

and ABC is also a isosceles triangle so AB is equal to AC

so by SSS criterion ∆ABD is congruent to ∆ ACD

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