Question

Answer this please urgent​

Answer 1

Thanks for your question...

Your required answer :

• PQRS is a parallelogram
• PQRS is a parallelogramPQ // RS
• PQRS is a parallelogramPQ // RSPS // QR

PQRS is a parallelogramPQ // RSPS // QRSo ,

• PQRS is a parallelogramPQ // RSPS // QRSo ,PQ = RS
• PQRS is a parallelogramPQ // RSPS // QRSo ,PQ = RSBR = PA
• PQRS is a parallelogramPQ // RSPS // QRSo ,PQ = RSBR = PATherefore APBR is a parallelogram .

PQRS is a parallelogramPQ // RSPS // QRSo ,PQ = RSBR = PATherefore APBR is a parallelogram .Now ,

• PQRS is a parallelogramPQ // RSPS // QRSo ,PQ = RSBR = PATherefore APBR is a parallelogram .Now ,In ∆ QTP
• PQRS is a parallelogramPQ // RSPS // QRSo ,PQ = RSBR = PATherefore APBR is a parallelogram .Now ,In ∆ QTPA is mid point of PQ .
• PQRS is a parallelogramPQ // RSPS // QRSo ,PQ = RSBR = PATherefore APBR is a parallelogram .Now ,In ∆ QTPA is mid point of PQ .AU // PT

Now by using converse of mid point theorem :

• Now by using converse of mid point theorem :QU = UT ---- ( 1 )
• Now by using converse of mid point theorem :QU = UT ---- ( 1 )Therefore PB and AR bisect SQ .

• In ∆ URS
• In ∆ URS B is mid point of SR
• RU // TB

By converse of Mid Point Theorem :

• UT = TS ---- ( 2 )

From equation 1 and equation 2 :

• ST = UT = UQ

Thus we can say that line segment PB and AR trisect the Diagonal SQ

Brainliest Please