answer this pls everyone
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The answer is down there for question no. 8
Pls check it
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banothmithila:
Question no. 7
1176 on prime factorisation is 2^3*3^1*7^2.
Therefore a=3
b=1 , c=2
a^a*b^b*7^(-c)=3^3*1^1*7^(-2)=27*1/49
=27/49
this is the answer for the question number 7
sorry had to write it this way
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For question 7 prime factorise then you can see powers of 2 ie a is equal to the number of times a come then substitute values you get your ans as 3^3×(1^1)×(1\49) hence answer is 0ption 2
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