Physics, asked by arkaop, 4 months ago

Answer this pls fast ....

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Answered by kikibuji
1
  • Velocity of the stone, u = 20 m/s

  • Angle with respect to horizontal, Ѳ = 30°

  • Acceleration due to gravity, g = 10 m/s²

1.MAXIMUM HEIGHT: Option c.

H= (u²sin²Ѳ)/2g

 =  \dfrac{ {(20)}^{2}  \times  ({ \sin(30) })^{2} }{2 \times 10} \\  \\  =  \dfrac{400 \times  { (\dfrac{1}{2}) }^{2} }{20}  \\  \\  =  \dfrac{400 \times  \dfrac{1}{4} }{20}   \\  \\  =  \dfrac{400}{20 \times 4}  \\  \\  =  \frac{100}{20} \\  \\  H= 5 \: m

The maximum height is 5 m.

2.TIME OF FLIGHT : option b.

T = (2u sinѲ) / g

 =  \dfrac{2 \times 20 \times  \sin(30) }{10}  \\  \\  =  \dfrac{40 \times  \dfrac{1}{2} }{10}  \\  \\  =  \dfrac{40}{10 \times 2}  \\  \\  =  \frac{40}{20}  \\  \\ T= 2 \: sec

The time of flight is 2 seconds.

3.RANGE : option b

R = (u²sin2Ѳ) / g

 =  \dfrac{ {(20)}^{2}  \times  \sin(2 \times 30) }{10}  \\  \\  =  \dfrac{400 \times  \sin(60) }{10}  \\  \\  =  \dfrac{400 \times  \dfrac{ \sqrt{3} }{2} }{10}  \\  \\  =  \dfrac{400 \times  \sqrt{3} }{10 \times 2}  \\  \\  R= 20 \sqrt{3}  \: m

Range is 20√3 m.

4.MAXIMUM RANGE : option b

Range is maximum when Ѳ is 45°

R = (u²sin2Ѳ) / g

 =  \dfrac{ {(20)}^{2}  \times  \sin(2 \times 45) }{10}  \\  \\  =  \dfrac{400 \times  \sin(90) }{10}  \\  \\  =  \dfrac{400 \times 1}{10}  \\  \\  =  \dfrac{400}{10}  \\  \\ R = 40 \: m

Maximum range is 40 m.

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