Answer this pls. Here i is iota
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(i)x2 - 5ix – 6 = 0 (ii) x2 + 4ix – 4 = 0
Solution: (i) The given equation is x2 - 5ix – 6 = 0
=> x2 - 5ix + 6i2 = 0
=> x2 - 3ix – 2ix + 6i2 = 0
=> x(x – 3i) – 2i(x – 3i) = 0
=> (x – 3i)(x – 2i) = 0
=> x – 3i = 0, x – 2i = 0
=> x = 3i, x = 2i
Hence, the roots of the given equation are 3i and 2i.
Solution: (i) The given equation is x2 - 5ix – 6 = 0
=> x2 - 5ix + 6i2 = 0
=> x2 - 3ix – 2ix + 6i2 = 0
=> x(x – 3i) – 2i(x – 3i) = 0
=> (x – 3i)(x – 2i) = 0
=> x – 3i = 0, x – 2i = 0
=> x = 3i, x = 2i
Hence, the roots of the given equation are 3i and 2i.
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