Question

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Answer 1

Answer:

this is the answer for your question.....

Answer 2

to prove ∆ACE~∆DBF

CE=BF(given)

AB+BC=BC+CD(add BC as common in both side

angle ACE=angle FBD(angles between equal sides

So,∆ACE~∆DBF (proved)

So,AE=FD (by CPCT)

hope this answer us useful for uh