Answer this pls no.2
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since average velocity= total displacement/time taken during travel.
t1=x/v1
t2=x/v2. t1+t2=x/v1+x/v2=x(1/v1+1/v2)=x(v1+v2)/v1v2
v avg.=(x+x)/(t1+t2)
=2x/(x*(v1+v2)/v1v2
=2v1v2/(v1+v2)
or this can be written as
2/v=(v1+v2)/v1v2=1/v2+1/v1
so the choice c is correct.
i hope you got it.
t1=x/v1
t2=x/v2. t1+t2=x/v1+x/v2=x(1/v1+1/v2)=x(v1+v2)/v1v2
v avg.=(x+x)/(t1+t2)
=2x/(x*(v1+v2)/v1v2
=2v1v2/(v1+v2)
or this can be written as
2/v=(v1+v2)/v1v2=1/v2+1/v1
so the choice c is correct.
i hope you got it.
mahendrachoudhary123:
if any problem than ask without any hesitation.but don't ask if you didn't understand calculation.because that is basic.
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