Chemistry, asked by ksysshsn, 1 day ago

answer this pls.. shiys sks s s​

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Answered by moraisaaria
0

Answer:

answer is option

C) During it's motion from O to A and back to O.

Explanation:

question says that distance should be maximum and displacement should me minimum.

for option A) From O to A and back to B.

distance from O to A = 60km

for A to B (as it comes back after reaching A to point B)

distance from A to B = 25km.

total distance travelled = 60+25 = 85km.

Displacement is the direct distance between the starting and end point. It doesn't care about how you took the to reach that end point i.e irrespective of the path covered.

so if we look direct start and end point distance then ,

---> O to B is = 35km.

distance = 85km

displacement = 35km.

similarly for option B) from O to A and back to C.

Distance from O to A = 60km

Distance from A to C = 35km

Total distance travelled = 95km

Displacement ( O to C ) = 25km

Distance = 95km

Displacement = 25km

option C) from O to A and back to O.

Distance from O to A = 60km

Distance from A to O = 60km

Total distance travelled = 120km

Displacement (O to O) = 0km

since start and end is same so if we overall there is no displacement done .

Distance = 120km

Displacement = 0km

option D) from O to A

Distance from O to A = 60km

Total distance travelled = 60km

Displacement ( O to A ) = 60km

Distance = 60km

Displacement = 60km

so if we compare all the options Distance and Displacement we will found that,

option C) from O to A and back to O

has maximum distance i.e 120km

and minimum displacement i.e 0km.

Thank you.

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