answer this pls. ya
I am requesting u my friends
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3) The number of zeroes is determined by the highest degree of the polynomial. Here it is 2.
4) putting x= -1 [-4(-1)²+5(-1)+3]
= [-4×1+(-5)+3]
= [-4-5+3]
= [-9+3]
= -6
5) p(x) = ax
a = 0
then 0 × X = 0
6) p(x)= x³+2x²-x+4
putting x = 1
= (1)³ + 2(1)² - (1) + 4
= 1+2-1+4
= 6.
Now, putting x = -2
= (-2)³ + 2(-2)² -(-2) +4
= -8+8+2+4
= 6.
HOPE IT HELPED YOU.....
4) putting x= -1 [-4(-1)²+5(-1)+3]
= [-4×1+(-5)+3]
= [-4-5+3]
= [-9+3]
= -6
5) p(x) = ax
a = 0
then 0 × X = 0
6) p(x)= x³+2x²-x+4
putting x = 1
= (1)³ + 2(1)² - (1) + 4
= 1+2-1+4
= 6.
Now, putting x = -2
= (-2)³ + 2(-2)² -(-2) +4
= -8+8+2+4
= 6.
HOPE IT HELPED YOU.....
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