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11. i)
We have, 2 sin 2 θ = √3
sin 2 θ = √3/2
sin 2 θ = sin 60°
2 θ = 60°
θ= 60°/2
θ = 30°
ii) (i) 2cos3θ=1
⇒cos3θ=21
⇒cos3θ=cos60
Therefore, 3θ=60
⇒θ=20
iii)
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