Physics, asked by chaithu80, 1 year ago

answer this plz...................

Attachments:

Anonymous: How did u write? It was a tougj one

Anonymous: Tough*

RajivShastry: Im in class 12

RajivShastry: Answer to the 1st is also 500J dude

Anonymous: Oh.. Sorry..i did not know

Anonymous: No the first answer is 300

RajivShastry: Nope

Anonymous: Bcoz he told to take 2m as the height.

Anonymous: I remember doing that way..

Anonymous: I dont know..

Answers

Answered by RajivShastry

At height of 2m

Total E = KE + PE

From 3rd equation of motion,

v²-u² = 2gs

v² = 2 (10)(3)

v² = 60 m²/s²

KE = mv²/2

KE = 10 X 60 / 2

KE = 300 J

PE = m g h = 10(10)(2) = 200 J

TE = 500 J

Before hitting,

PE = 0

KE = mv²/2

v² = 2gh = 2(10)5

v² = 100

KE = 10 X 100/2

KE = 500J

Anonymous: Okay..

Anonymous: Thank you soooo much for your guidance...

Anonymous: Thanks

RajivShastry: I don't know abt Hyd branches but here it's good

Anonymous: Oh.. Okay.. Here also they are good

RajivShastry: ok

Anonymous: Hmm thanks

Anonymous: Byee.. Preparing for my matsh exam

Anonymous: Maths*

RajivShastry: Bye

Previous Question

Next Question