answer this plz fast
Answers
Ordinate of the point (y) = 3
Step-by-step explanation:
Let \:A(x,y) = (10,y) ,and \:P(2,-3)LetA(x,y)=(10,y),andP(2,−3)
AP = 10\:(given)AP=10(given)
\begin{gathered} By\: distance \: formula:\\If \: A(x_{1},y_{1})\:and\:B(x_{2},y_{2})\:then \\Distance (AB) =\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\end{gathered}
Bydistanceformula:
IfA(x
1
,y
1
)andB(x
2
,y
2
)then
Distance(AB)=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
\begin{gathered}Now,PA = 10\\PA^{2}= 10^{2}\\(10-2)^{2}+[y-(-3)]^{2}=100\end{gathered}
Now,PA=10
PA
2
=10
2
(10−2)
2
+[y−(−3)]
2
=100
\implies 8^{2}+(y+3)^{2}=100⟹8
2
+(y+3)
2
=100
\implies 64+(y+3)^{2}=100⟹64+(y+3)
2
=100
\implies (y+3)^{2}=100-64=36⟹(y+3)
2
=100−64=36
\implies y+3 = \sqrt{36}⟹y+3=
36
\implies y+3 = 6⟹y+3=6
\implies y = 6-3=3⟹y=6−3=3