answer this plz ..........with explanation
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smruti2002:
how
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Answered by
1
sin51° + cos81°,
sin(90°-39°) + cos81°
cos39° + cos81°,
we can write it as,
cos81° + cos39°,
2 cos(81°+39°)/2 . cos(81°-39°)/2,
2 cos120°/2 . cos42°/2,
2 cos60° . cos21°,
2 × 1/2 . cos21°,
cos21°✓✓✓✓✓✓
since cosC + cosD = 2 cos(C+D)/2 . cos(C-D)/2
sin(90°-39°) + cos81°
cos39° + cos81°,
we can write it as,
cos81° + cos39°,
2 cos(81°+39°)/2 . cos(81°-39°)/2,
2 cos120°/2 . cos42°/2,
2 cos60° . cos21°,
2 × 1/2 . cos21°,
cos21°✓✓✓✓✓✓
since cosC + cosD = 2 cos(C+D)/2 . cos(C-D)/2
Answered by
1
hey here is ur answer in attachment
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