Answer this plzz
Im stuck!!
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Answer:
I think 202......
But I am not sure....
Sorry can't really help you
Answer:
202
Step-by-step explanation:
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Asked on October 15, 2019 by
Janak Che
The number of terms in the expansion off (1+x)
101
(1+x
2
−x)
100
in power of x is :
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VIDEO EXPLANATION
ANSWER
(1+x)
101
(1−x+x
2
)
100
can be written as
=(1+x)(1+x)
100
(1−x+x
2
)
100
=(1+x)[(1+x)(1−x+x
2
)]
100
=(1+x)(1+x
3
)
100
=(1+x
3
)
100
+x(1+x
3
)
100
Number of terms in (1+x
3
)
100
=101[terms are a
0
+a
1
x
3
+a
2
x
6
+............+a
1
00x
300
]
Number of terms in x(1+x
3
)
100
=101[terms are a
0
x+a
1
x
4
+a
2
x
7
+............+a
1
00x
301
]
since there are no common terms
.
So, number of terms in (1+x)(1+x
3
)
100
=101+101=202