Question

answer this plzzzzzzzzz

Answer 1

$x = 1 - \sqrt{2}$
$\frac{1}{x} = \frac{1}{1 - \sqrt{2} } \times \frac{1 + \sqrt{2} }{1 + \sqrt{2} } \\ \\ \frac{1}{x} = \frac{1 + \sqrt{2} }{1 - 2} \\ \\ \frac{1}{x} = \frac{1 + \sqrt{2} }{ - 1} \\ \\ \frac{1}{x} = - (1 + \sqrt{2} )$

Now,

${(x - \frac{1}{x}) }^{4} = {(1 - \sqrt{2} - ( - 1 - \sqrt{2} )) }^{4} \\ \\ = {(1 - \sqrt{2} + 1 + \sqrt{2} )}^{4} \\ \\ = {2}^{4} \\ \\ = 16$