answer this problem
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a + 1/a = b , then a³ + 1/a³ = ?
=> [a + 1/a]³ = b³ [ cubing both sides ]
=> a³ + 1/a³ + 3*a*1/a [ a + 1/a ] => b³
=> a³ + 1/a³ + 3 [ b ] => b³
=> a³ + 1/a³ = b³ - 3b
=> a³ + 1/a³ = b (b² - 3)
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