Math, asked by shalini7187, 2 months ago

answer this problem

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Answered by biligiri
0

Answer:

a + 1/a = b , then a³ + 1/a³ = ?

=> [a + 1/a]³ = b³ [ cubing both sides ]

=> a³ + 1/a³ + 3*a*1/a [ a + 1/a ] => b³

=> a³ + 1/a³ + 3 [ b ] => b³

=> a³ + 1/a³ = b³ - 3b

=> a³ + 1/a³ = b (b² - 3)

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