Math, asked by jaswasri2006, 5 months ago

Answer this properly

This 50 points is worth so answer properly

Questions :-

1. Leena is 4 years younger than Jaya now . Frame an expression for their ages after 10 years .


2. Lucky is 4 times old as Ali . If Ali is “ x ” years old , what is Lucky's age after 6 years hence ?

3. Rahul spends ₹y daily and saves ₹z per week . What is his income for three weeks ?

4. Reema has 12a flowers . Ria has 6 flowers more than Reema . How many flowers does Ria ?


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Answers

Answered by biligiri
0

Step-by-step explanation:

1) jaya 's present age be x

Leena's present age = x - 4

after 10 years

jaya's age = x + 10

Leena's age = x - 4 + 10 => x + 6

2) Ali's present age = x

Lucky's present age = 4x

After 6 years,

Ali's age => x + 6

Lucky's age => 4x + 6

Answered by Aadarshini6A1
1

Step-by-step explanation:

1. JAYA'S PRESENT AGE = X

LEENA'S PRESENT AGE= X-4

after 10 yrs

JAYA'S AGE = x+10

LEENA'S AGE = X-4+10=> X+6

2. LUCKY PRESENT AGE=4X

ALI'S PRESENT AGE - X

AFTER 6 YEARS

ALI'S AGE X+6

LUCKY AGE-4X + 6

3. Amount of money spend in 1 day =  x

So, amount of money spend in 7 days =  (7x)

⇒  Amount of money spend in 1 week =  (7x)

Amount of money saved in 1 week =  y

∴  Income in 1 week =  (7x + y)

So, income in 3 weeks =  [3 x (7x + y)]

=  (21x + 3y)

4. -

PLS MARK AS BRAINLIEST

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