Question

answer this queation it will help me​

Answer 1

cot(theta)=3/4=base/height

therefore the hypotenuse is

$\sqrt{4 {}^{2} +3 {}^{2} } = 5$

therefore

....cosec(theta)=hypotenuse/height=5/4

and ...cos(theta)=base/hypotenuse=3/5

therefore...4cosec(theta)+5cis(theta)

=4(5/4)+5(3/5)

=5+3

=8

there