Math, asked by ksashwinkumar81, 7 months ago

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i need this urgenty
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Answered by ItzDeadDeal
3

Answer:

\begin{gathered}x = \frac{81}{64} \\ \\ Given\ expr\ E = \sqrt{x \sqrt {x\sqrt{x\ ...}}} \\ \\ E = \sqrt{x E} \ \ \ \ \ So,\ \ \ E^2 = x E \ \ \ \ E = x = \frac{81}{64}\ OR,\ another\ way, \\ \\ E = x^{\frac{1}{2}+\frac{1}{4}+\frac{1}{8}...} = x^1 = x = \frac{81}{64} \\ \\ \\ Y = \sqrt{10+\sqrt{24}+\sqrt{60}+\sqrt{40}} \\ \\ Y^2 = 10 + \sqrt{24}+\sqrt{60}+\sqrt{40} \\\end{gathered} </p><p>[

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