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vrkgayathri10:
Should I have to prove that??
no
if u now the value pls tell
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Answered by
1
Answer:55
Step-by-step explanation:
just open the brackets,
after opening brackets, we get,
(2x+2y+2z+2a+2b+2c+2d+2p+2q+2r)-2-4-6-8-10-12-14-16-18-20=0
taking 2 common from variables,and take the no.s on the other side of equal sign
2(x+y+z+a+b+c+d+p+q+r)=110
dividing both sides by 2, we get
x+y+z+a+b+c+d+p+q+r=55
let me one answer is it 110 or 55
take 2 common from all of the above and by transformation we get that x+y+z+a+b+c+d+p+q+r=55
it is 55
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Answered by
1
Answer:
2 (x+y+z+a+b+c+d+p+q+r)-(2+4+6+8+10+12+14+16+18+20)=0
or,2 (x+y+z+a+b+c+d+p+q+r)=110
or, (x+y+z+a+b+c+d+p+q+r)=110/2=55 ans.
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any doubt or more problems? ?
naa
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