Question

Answer this question​

Answer 1

Answer:

Let numbers be x at ones place and y at tens place so

10y+x is that digit

now reversed digit is 10x+y

according to question

7 (10y+x)=4(10x+y)

x=2y (i)

now

given

x-y=3

from eq. i 2y=x

2y-y=3

y=3

so

x=63

required original no. is 36 and reversed digit is 63

I HOPE THIS WILL HELPFULL TO YOU

Answer 2

Answer:

HEY MATE HERE IS YOUR ANSWER