Physics, asked by Foamy, 10 months ago

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Answered by Anonymous
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Answer:

100m {s}^{ -  2}

Explanation:

given \:  \: u = initial \: velocity \:  = 40m {s}^{ - 1}  \\ v \:  = final \: velocity \:  = 0 \: (since \: the \: body \: came \: to \: rest) \\ s = displacement \:  = 8m \\ we \: know \: that \:  {v}^{2}  -  {u}^{2}  = 2as \\  {0}^{2}  -  {40}^{2}  = 2(a)(8) \\  - 1600 = 16a \\ a \:  = 100 m {s}^{ - 2}  \\ there \: fore \: the \: acceleration \: experienced \: i \:  - 100m {s}^{ - 2}  \\ and \: retardation \:  =  - a =  - ( - 100) = 100m {s}^{ - 2}

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