Physics, asked by lotus187, 10 months ago

answer this question....​

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Answered by peekaboo45
1

Answer:

let it takes t second to reach the top of the window.

So it will take (t+0.1) s to reach the bottom of the window.

distance between them = 2m

So

(0×t + 0.5×10×(t+0.1)²) - (0×t + 0.5×10×(t)²) = 2

⇒ 5(t+0.1)² - 5t² = 2

⇒ 5(t² + 0.01 + 0.2t) - 5t² = 2

⇒ 5t² + 0.05 + t - 5t² = 5

⇒ t + 0.05 = 2

⇒ t = 5 - 0.05 = 4.95s

Distance of top of window = 0.5×10×4.95² = 5×24.5025 = 122.5m

Answered by goru63
2

Answer:

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