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Let the distance of a one side trip be d.
For one side of the trip, average speed is 20kmph.
So time for the journey = distance / speed
= d/20
For the other side of the trip, average speed is 30kmph.
So time for the journey = distance / speed
= d/30
net average speed = total distance/total time
= (d +d )/(d/20+d/30)
= 2d/(d/20+d/30)
= 2/(1/20+1/30)
= 2/ (5/60)
= 24 kmph
Hence, the net average speed of Abdul's journey is 24 kmph.
Hope you understand the concept.
All the best.
For one side of the trip, average speed is 20kmph.
So time for the journey = distance / speed
= d/20
For the other side of the trip, average speed is 30kmph.
So time for the journey = distance / speed
= d/30
net average speed = total distance/total time
= (d +d )/(d/20+d/30)
= 2d/(d/20+d/30)
= 2/(1/20+1/30)
= 2/ (5/60)
= 24 kmph
Hence, the net average speed of Abdul's journey is 24 kmph.
Hope you understand the concept.
All the best.
Abhay41:
thanks for your answer
no problem
why did you write 2/(5/60). how did 5 came there
d gets cancelled from numerator and denominator
in the denominator it remains (1/20+ 1/30)
what is it equal to?
5/60? or not?
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