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Let the distance of a one side trip be d.
For one side of the trip, average speed is 20kmph.
So time for the journey = distance / speed
= d/20
For the other side of the trip, average speed is 30kmph.
So time for the journey = distance / speed
= d/30
net average speed = total​ distance/total time
= (d +d )/(d/20+d/30)
= 2d/(d/20+d/30)
= 2/(1/20+1/30)
= 2/ (5/60)
= 24 kmph
Hence, the net average speed of Abdul's journey is 24 kmph.
Hope you understand the concept.
All the best.
For one side of the trip, average speed is 20kmph.
So time for the journey = distance / speed
= d/20
For the other side of the trip, average speed is 30kmph.
So time for the journey = distance / speed
= d/30
net average speed = total​ distance/total time
= (d +d )/(d/20+d/30)
= 2d/(d/20+d/30)
= 2/(1/20+1/30)
= 2/ (5/60)
= 24 kmph
Hence, the net average speed of Abdul's journey is 24 kmph.
Hope you understand the concept.
All the best.
Abhay41:
thanks for your answer
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