Question

answer this question.....​

Answer 1

Step-by-step explanation:

let 2^x = y

${ ({2}^{x}) }^{2} - {2}^{x} . {2}^{3} + {2}^{4 } = 0 \\ {y}^{2} - 8y + 16 =0 \\ {(y - 4)}^{2} = 0 \\ y = 2 \\ {2}^{x} = {2}^{1} \\ x = 1$