Question

answer this question

Answer 1

Hey there !!!!!!

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=(α²/β)¹/³+(β²/α)¹/³

=((α³)¹/³+(β³)¹/³)/(αβ)¹/³

=(α+β)/(αβ)¹/³

Quadratic equation of form ax²+bx+c=0

α+β=-b/a  αβ=c/a

Comparing 8x²-3x+27=0 with ax²+bx+c=0

a=8 b=-3 c=27

α+β=-b/a = 3/8

αβ=c/a=27/8

=(α+β)/(αβ)¹/³

=3/8/(27/8)¹/³

27=3³ 8=2³

(27/8)¹/³ = 3³/³/2³/³ = 3/2


=3/8/(27/8)¹/³

=3/8/3/2

=2/8

=1/4

(α²/β)¹/³+(β²/α)¹/³ =1/4

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Hope this helped you...................