Question

answer this question..........​

Answer 1

pls mark me as brainliest

Answer 2

Answer:

$\frac{6 {x}^{2} + 6(x + 1)(x + 1) }{x(x + 1)} = 13 \\ \frac{6 {x}^{2} + 6( {x}^{2} + 2x + 1 ) }{ {x}^{2} + x } = 13 \\ \frac{12 {x}^{2} + 12x + 6}{ {x}^{2} + x} = 13 \\ 12 {x}^{2} + 12x + 6 = 13 {x}^{2} + 13x \\ {x}^{2} + x - 6 = 0 \\ {x}^{2} + 3x - 2x - 6 = 0 \\ x(x + 3) - 2(x + 3) = 0 \\ x = 2 \: or \: - 3$