Question

Answer this question...​

Answer 1

Answer:

Step-by-step explanation: According to question 4q2 = p2+ 3r2.  

Answer 2

Answer:

We have to prove 4b^2=a^2+3r^2

We have to prove 4b^2=a^2+3r^2Let AC =q then AB=2q

Now take OE perpendicular to AC and OF perpendicular to AB.

In∆ OEA,

OA^2 = OE^2 + AE^2

r^2=b^2+ a^2/4

4r^2=4b^2+q^2

q^2=4r^2 - 4b^2 ....... eq 1

In ∆ OFA,

OA^2=OF^2+AF^2

r^2 = a^2 +q^2

q^2= r^2 -a^2. .........eq 2

Now by eq 1 and eq 2 ,we can write

r^2-a^2=4r^2 -4b^2

then,

4b^2=3r^2+a^2.

Hence proved.