Question

Answer this question....

Answer 1

here you go.
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Answer 2

Hey there!!!

Taking zero of potential energy at infinity, we get potential energy (P.E.) of the system of charges,
P.E. = 1 /  (4π∈°) ∑(all pairs) q j . q k / r jk
        = 1 / (4π∈°) [qq/a + q(-q)/a + (-q)(-q)/a + (-q)(+q)/a + q(-q)/a√2 + q(-q)/a√2]
        = 1 / (4π∈°) [q²/a - q²/a + q²/a - q²/a - q²/a√2 - q²/a√2]
        = 1 / (4π∈°) (-2q²/a√2)

P.E. = q²/4π∈°a (-√2)



HOPE IT HELPS!!