Question

answer this question ​

Answer 1

let the larger no be x and smaller no be y

x=4y+3 (I)

7y=5x+1. (ii)

substituting value of x from (I)

7y= 5(4y+3) +1

7y = 20y + 15 +1

-13 y= 16

y= -16/13

x= 4×-16/13+3

x=-64+39/13

x= -25/13