answer this question
Attachments:
Answers
Answered by
1
let the larger no be x and smaller no be y
x=4y+3 (I)
7y=5x+1. (ii)
substituting value of x from (I)
7y= 5(4y+3) +1
7y = 20y + 15 +1
-13 y= 16
y= -16/13
x= 4×-16/13+3
x=-64+39/13
x= -25/13
Similar questions