Biology, asked by sandeep6836, 1 year ago

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Answered by rani49035
0

Explanation:

Mendel crossed two pea plants differing in contrasting traits of two characters i.e a dihybrid cross.

He crossed a pea plant having yellow coloured and rounded seeds with another pea plant having green coloured and wrinkled seed.

The F$$_1$$ generation has all round and yellow seeds.

The F$$_2$$ generation, all the characters inherited independently. (round yellow, round green, wrinkled yellow, wrinkled green.

Answered by DevanshiS
0

When a pea plant with wrinkled green seeds was crossed with a pea plant with round yellow seeds, the F1 progeny produced were all plants having round yellow seeds. It means that round and yellow seeds are dominant traits while wrinkled green seeds are recessive traits. When the F1 progeny was self-pollinated and F2 progeny was fenerated, there were four types of plants produced:

  1. Round yellow seeds= 9
  2. Round green seeds= 3
  3. Wrinkled yellow seeds= 3
  4. Wrinkled green seeds = 1

P.S Draw the cross and the Punnett square

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